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Vectorial Analysis
Vectorial Analysis
Vectorial Analysis
Libro electrónico87 páginas57 minutos

Vectorial Analysis

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The solution for the problems presented in this book are solved with algebra, analytic geometry, differential and integral calculus geometry, MATLAB and vector analysis.
IdiomaEspañol
EditorialPalibrio
Fecha de lanzamiento31 jul 2012
ISBN9781463329761
Vectorial Analysis

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    Vectorial Analysis - Ing. Mario Castillo

    Copyright © 2012 por Ing. Mario Castillo.

    Todos los derechos reservados. Ninguna parte de este libro puede ser reproducida o transmitida de cualquier forma o por cualquier medio, electrónico o mecánico, incluyendo fotocopia, grabación, o por cualquier sistema de almacenamiento y recuperación, sin permiso escrito del propietario del copyright.

    Las opiniones expresadas en este trabajo son exclusivas del autor y no reflejan necesariamente las opiniones del editor. La editorial se exime de cualquier responsabilidad derivadas de los mismos.

    Para pedidos de copias adicionales de este libro, por favor contacte con:

    Palibrio

    1663 Liberty Drive

    Suite 200

    Bloomington, IN 47403

    Llamadas desde los EE.UU. 877.407.5847

    Llamadas internacionales +1.812.671.9757

    Fax: +1.812.355.1576

    ventas@palibrio.com

    408317

    Contents

    Prologue

    Chapter I Vector And Scalars

    Chapter II The Dot And Cross Product

    Chapter III Vector And Scalars

    Chapter IV Gradient

    Chapter V Vector Integration

    Chapter VI

    Bibliography

    PROLOGUE

    THE SOLUTION FOR THE PROBLEMS PRESENTED IN THIS BOOK ARE SOLVED WITH ALGEBRA, ANALYTIC GEOMETRY, DIFFERENTIAL AND INTEGRAL CALCULUS GEOMETRY, MATLAB AND VECTOR ANALYSIS.

    CHAPTER I ARE VECTOR AND SCALARS, WE SOLVE PROBLEMS OF PHYSICS (FORCES) AND DYNAMICS.

    CHAPTER II DOT AND DOT PRODUCT, WE SOLVE PROBLEMS OF ADD, SUBTRACT, MULTIPLY AND VECTOR DIVISION IN THREE DIMENSIONS, ANGLES AND PLANES.

    CHAPTER III DERIVATION OF VECTORS AND SCALARS, VELOCITY AND ACCELERATION AND ITS DIAGRAMS (VISUALIZATION). IN THREE DIMENSIONS.

    CHAPTER IV GRADIENT OF ADD, SUBTRACT MULTIPLY AND DIVIDE FUNCTIONS. GRAPHICS IN TRIDIMENSIONAL FUNCTIONS, PERPENDICULAR VECTOR AT A SURFACE. ONE FUNCTION.

    CHAPTER V. VECTOR INTEGRATION PROBLEMS OF VELOCITY AND ACCELERATION OF PARTICLES IN ONE PATH, FORCE BY DISTANCE. UNIT VECTORS.

    CHAPTER VI. TRANSFORMATION OF COORDINATES SPHERICAL, CYLINDRICAL, PARABOLIC, ELLIPTIC UNIT VECTORS, VECTORS, ORTHOGONAL FUNCTIONS, THREE DIMENSION GRAPHICS.

    THE AUTHOR OF THIS BOOK THANKS AT THE INSTRUCTORS OF THE ELECTRICAL ENGINEERING DEPARTMENT THE UNIVERSITY OF TEXAS PAN AMERICAN OF EDINBURG, DR HEINRICH FOLTZ AND DR BEN GHALIA MOUNIR BY ALL ITS ADVISES.

    CHAPTER I

    VECTOR AND SCALARS

    1 WHICH OF THE FOLLOWING ARE SCALARS AND WHICH ARE VECTORS?

    2 AN AIRPLANE TRAVELS 200 MILES DUE WEST AND THEN 150 MILES 60 DEGREES NORTH OF WEST. DETERMINE THE RESULTANTE DISPLACEMENT.

    R1 = 200;

    ANG1 = pi;

    R2 = 150;

    ANG2 = 2*pi/3;

    Rx = (R1*cos (ANG1) + R2*cos (ANG2));

    Ry = R1*sin (ANG1) + R2*sin (ANG2);

    R = (Rx^2 + Ry^2) ^.5;

    fprintf (‘R %f /n', R);

    fprintf (‘Rx %f /n', Rx);

    fprintf (‘Ry %f /n', Ry);

    theta = (180/pi)*(atan(Ry/Rx));

    fprintf('theta %f /n', theta);

    RESULT R = 304.138127 /n Rx= -275.000000 /n Ry = 129.903811 /n

    Theta = -25.284996 /n

    3 FIND THE RESULTANT OF THE FOLLOWING DISPLACEMENTS: A. 20 MILES 30º SOUTH OF EAST; B. 50 MILES DUE WEST; C. 40 MILES NORTHEAST; D. 30 MILES 60 DEGREES SOUTH H OF WEST.

    R1 = 20;

    ANG1 = - pi/6;

    R2 = 50;

    ANG2 = - pi;

    R3 = 40;

    ANG3 = pi/4;

    R4 = 30;

    ANG4 = - 2*pi/3;

    Rx = R1*cos(ANG1) + R2*cos(ANG2) + R3*cos(ANG3) + R4*cos(ANG4);

    Ry = R1*sin(ANG1) + R2*sin(ANG2) + R3*sin(ANG3) + R4*sin(ANG4);

    R = ( Rx^2 + Ry^2)^.5;

    fprintf('R %f /n', R);

    fprintf('Rx %f /n', Rx);

    fprintf('Ry %f /n', Ry);

    theta = (180/pi)*(atan(Ry/Rx));

    SOLUTION R 20.866494 /nRx -19.395221 /nRy -7.696491 /n

    4 SHOW GRAPHICALLY THAT - (A - B) = - A + B

    image006.jpg

    5 F ABCDEF ARE THE VERTICES OF A REGULAR HEXAGON, FIND THE RESULTANT OF THE FORCES REPRESENTED BY THE VECTORS AB, AC, AD, AE AND AF.

    image008.jpg

    Fx = 150 + 200(cos 30) = 150 + 173.2 = 323.2lb

    Fy = 100 - 200(sin (30)) = 100 - 100 = 0 lb

    6 IF A AND B ARE GIVEN VECTORS SHOW THAT (A) | A + B | <= | A | + B

                                                                    ( B ) | A - B | < = | A | - | B |

    = Ax + Ay, B = Bx + By

    |A + B| = |Ax + Bx + Ay + By| <= | Ax + Ay| +

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